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JEE MAIN_2021_
27-07-21
Question
When 400 mL of $0.2 \mathrm{M} \mathrm{H}_2 \mathrm{SO}_4$ solution is mixed with 600 mL of 0.1 M NaOH solution, the increase in temperature of the final solution is $\_\_\_\_$ $\times 10^{-2} \mathrm{~K}$. (Round off to the nearest integer). [Use: $\mathrm{H}^{+}(\mathrm{aq})+\mathrm{OH}-(\mathrm{aq}) \rightarrow \mathrm{H}_2 \mathrm{O}$. $$ \left.\Delta \gamma \mathrm{H}=-57.1 \mathrm{~kJ} \mathrm{~mol}^{-1}\right] $$ Specific heat of $\mathrm{H}_2 \mathrm{O}=4.18 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~g}^{-1}$ density of $\mathrm{H}_2 \mathrm{O}=1.0 \mathrm{~g} \mathrm{~cm}^{-3}$ Assume no change in volume of solution on mixing.
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JEE Main
Chemistry
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