The $71^{\text {st }}$ electron of an element X with an atomic number of 71 enters into the orbital:
Select the correct option:
A
5 d
B
6 p
C
4 f
D
6 s
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Atomic number = 71
Electronic configuration:
$[\mathrm{Xe}] 6 \mathrm{~s}^2 4 \mathrm{f}^{14} 5 \mathrm{~d}^1 \leftarrow$ last electron
∴ Orbital occupied by last $\mathrm{e}^{-}$is 5 d
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