If ∫x⁵e⁻⁴ˣ³ dx = (1/48)e⁻⁴ˣ³ f(x)+C... | Integrals | JEE Main

JEE MAIN 2019

10-01-2019 S2

Question

If $\int x^5 e^{-4 x^3} d x=\frac{1}{48} e^{-4 x^3} f(x)+C$ where $C$ is a constant of integration, then $f(x)$ is equal to

Select the correct option:

A

$4 x^3+1$

B

$-4 x^3-1$

C

$-2 x^3+1$

D

$-2 x^3-1$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Medium

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