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JEE MAIN 2020
08-01-20 S2
Question
An electron (mass $m$ ) with initial velocity $\vec{v}=v_0 \hat{i}+v_0 \hat{j} \vec{E}=-E_0 \hat{k}$. If $\lambda_0$ is initial de-Broglie wavelength of electron, its de-Broglie wavelength at time $t$ is given by
Select the correct option:
A
$\frac{\lambda_0}{\sqrt{1+\frac{\mathrm{e}^2 \mathrm{E}_0^2 \mathrm{t}^2}{\mathrm{~m}^2 \mathrm{v}_0^2}}}$
B
$\frac{\lambda_0 \sqrt{2}}{\sqrt{1+\frac{\mathrm{e}^2 \mathrm{E}^2 \mathrm{t}^2}{\mathrm{~m}^2 \mathrm{v}_0^2}}}$
C
$\frac{\lambda_0}{\sqrt{1+\frac{e^2 E^2 t^2}{2 m^2 v_0^2}}}$
D
$\frac{\lambda_0}{\sqrt{2+\frac{e^2 E^2 t^2}{m^2 v_0^2}}}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Physics
Hard
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