If the following system of linear equations has no solution… | Determinants

JEE MAIN 2021

31-08-2021 S1

Question

If the following system of linear equations $\begin{aligned} & 2 x+y+z=5 \\ & x-y+z=3 \\ & x+y+a z=b, \text { has no solution, then: }\end{aligned}$

Select the correct option:

$a=-\frac{1}{3}, b \neq \frac{7}{3}$

$a \neq \frac{1}{3}, b=\frac{7}{3}$

$a \neq-\frac{1}{3}, b=\frac{7}{3}$

$a \neq \frac{1}{3}, b \neq \frac{7}{3}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

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