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JEE MAIN 2020
07-01-20 S1
Question
For the reaction $\mathrm{A}(\mathrm{l}) \rightarrow 2 \mathrm{~B}(\mathrm{~g})$ $\Delta \mathrm{U}=2.1 \mathrm{kcal}, \Delta \mathrm{S}=20 \mathrm{cal} \mathrm{K}^{-1}$ at 300 K . Hence $\Delta \mathrm{G}$ in kcal is $\_\_\_\_$ .
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Question Tags
JEE Main
Chemistry
Medium
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