For the reaction
$\mathrm{A}(\mathrm{l}) \rightarrow 2 \mathrm{~B}(\mathrm{~g})$
$\Delta \mathrm{U}=2.1 \mathrm{kcal}, \Delta \mathrm{S}=20 \mathrm{cal} \mathrm{K}^{-1}$ at 300 K .
Hence $\Delta \mathrm{G}$ in kcal is $\_\_\_\_$ .
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