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JEE MAIN 2019
09-01-19 S2
Question
A power transmission line feeds input power at 2300 V to a step down transformer with its primary windings having 4000 turns. The output power is delivered at 230 V by the transformer. If the current in the primary winding of the transformer is 5 A and its efficiency is $90 \%$, the output current would be:
Select the correct option:
A
25 A
B
50A
C
45A
D
35A
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$\begin{aligned} & P_{\text {irput }}=V_p-I_p=2300 \times 5 \mathrm{~W} \\ & P_{\text {output }}=0.9 P_{\text {iouput }}=V_s I_s \\ & \Rightarrow I_s=\frac{0.9 \times 2300 \times 5}{230}=45 \mathrm{~A}\end{aligned}$
Question Tags
JEE Main
Physics
Easy
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