The specific heat of water $=4200 \mathrm{~J} \mathrm{~kg}^{-1} \mathrm{~K}^{-1}$ and the latent heat of ice $=3.4 \times 105 \mathrm{~J} \mathrm{~kg}^{-1} .100$ grams of ice at $0^{\circ} \mathrm{C}$ is placed in 200 g of water at $25^{\circ} \mathrm{C}$. The amount of ice that will melt as the temperature of water reaches $0^{\circ} \mathrm{C}$ is close to (in grams)