Let then a and b are the roots quadratic

JEE MAIN 2020

08-01-20 S2

Question

Let $\alpha=\frac{-1+\mathrm{i} \sqrt{3}}{2}$. If $\mathrm{a}=(1+\alpha) \sum_{\mathrm{k}=0}^{100} \alpha^{2 \mathrm{k}}$ and $\mathrm{b}=\sum_{\mathrm{k}=0}^{100} \alpha^{3 \mathrm{k}}$, then a and b are the roots of the quadratic equation

Select the correct option:

$x^2-101 x+100=0$

$x^2-102 x+101=0$

$x^2+101 x+100=0$

$x^2+102 x+101=0$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Medium

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