A particle of mass m is fixed..|CIRCULAR MOTION|JEEMAIN 2020

JEE MAIN 2020

08-01-20 S1

Question

A particle of mass m is fixed to one end of a light spring having force constant k and unstretched length l. The other end is fixed. The system is given an angular speed  about the fixed end of the spring such that it rotates in a circle in gravity free space. Then the stretch in the spring is

Select the correct option:

$\frac{\mathrm{m} \mid \omega^2}{\mathrm{k}-\omega \mathrm{m}}$

$\frac{\mathrm{m} \mid \omega^2}{\mathrm{k}+\omega \mathrm{m}^2}$

$\frac{m \mid \omega^2}{k+m \omega}$

$\frac{m \mid \omega^2}{k-m \omega^2}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution