A submarine experiences a pressure of depth| FLUID MECHANICS

JEE MAIN 2019

10-04-2019 S2

Question

A submarine experiences a pressure of $5.05 \times 10^6$ Pa at a depth of $\mathrm{d}_1$ in a sea. When it goes further to a depth of $\mathrm{d}_2$, it experiences a pressure of $8.08 \times 10^6 \mathrm{~Pa}$. Then $\mathrm{d}_2-\mathrm{d}_1$ is approximately (density of water $=10^3 \mathrm{~kg} / \mathrm{m}^3$ and acceleration due to gravity $=10 \mathrm{~ms}^{-2}$ ):

Select the correct option:

600 m

500 m

300 m

400 m

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

$\begin{aligned} & \Delta P=P_2-P_1=\rho g \Delta H \\ & 3.03 \times 10^6=10^3 \times 10 \times \Delta H \\ & \Rightarrow \Delta H \simeq 300 \mathrm{~m}\end{aligned}$

Question Tags

JEE Main

Physics

Easy

Start Preparing for JEE with Competishun

Report Issue