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JEE MAIN 2020
08-01-20 S1
Question
Proton with kinetic energy of 1 MeV moves from south to north. It gets an acceleration of $10^{12} \mathrm{~m} / \mathrm{s}^2$ by an applied magnetic field (west to east). The value of magnetic field (Rest mass of proton is $1.6 \times 10^{-27} \mathrm{~kg}$ )
Select the correct option:
A
0.071 mT
B
0.71 mT
C
71 mT
D
7.1 mT
✓ Correct! Well done.
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Solution
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Question Tags
JEE Main
Physics
Medium
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