The pH of a.......................| IE

JEE MAIN 2019

10-04-2019 S2

Question

The pH of a $0.02 \mathrm{M} \mathrm{NH}_4 \mathrm{Cl}$ solution will be [given $$ \left.\mathrm{K}_{\mathrm{b}}\left(\mathrm{NH}_4 \mathrm{OH}\right)=10^{-5} \text { and } \log 2=0.301\right] $$

Select the correct option:

2.65

5.35

4.35

4.65

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Chemistry

Easy

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