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JEE MAIN_2021_
27-8-2021_S2
Question
If the solution curve of the differential equation $\left(2 x-10 y^3\right) d y+y d x=0$, passes through the points $(0,1)$ and $(2, \beta)$, then $b$ is a root of the equation:
Select the correct option:
A
$y^5-2 y-2=0$
B
$2 y^5-2 y-1=0$
C
$2 y^5-y^2-2=0$
D
$y^5-y^2-1=0$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Easy
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