The minimum amount of O2(g) consumed |MoleConceptJEEMAN2019

JEE MAIN 2019

10-04-2019 S2

Question

The minimum amount of O2(g) consumed per gram of reactant is for the reaction: (Given atomic mass : Fe = 56, O = 16, Mg = 24, P = 31, C = 12, H = 1)

Select the correct option:

$2 \mathrm{Mg}(\mathrm{s})+\mathrm{O}_2(\mathrm{~g}) \rightarrow 2 \mathrm{MgO}(\mathrm{s})$

$4 \mathrm{Fe}(\mathrm{s})+3 \mathrm{O}_2(\mathrm{~g}) \rightarrow 2 \mathrm{Fe}_2 \mathrm{O}_3(\mathrm{~s})$

$\mathrm{C}_3 \mathrm{H}_8(\mathrm{~g})+5 \mathrm{O}_2(\mathrm{~g}) \rightarrow 3 \mathrm{CO}_2(\mathrm{~g})+4 \mathrm{H}_2 \mathrm{O}(\mathrm{l})$

$\mathrm{P}_4(\mathrm{~s})+5 \mathrm{O}_2(\mathrm{~g}) \rightarrow \mathrm{P}_4 \mathrm{O}_{10}(\mathrm{~s})$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Chemistry

Easy

Start Preparing for JEE with Competishun