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JEE MAIN 2026
02-04-2026 S1
Question
The solubility product constants of $\mathrm{Ag}_2 \mathrm{CrO}_4$ and AgBr are 32 x and 4 y respectively at 298 K . The value of $\left(\frac{\text { molarity of } \mathrm{Ag}_2 \mathrm{CrO}_4}{\text { molarity of } \mathrm{AgBr}}\right)$ can be expressed as :
Select the correct option:
A
$\frac{2 \sqrt[3]{x}}{y}$
B
$2 \sqrt{\frac{x}{y}}$
C
$\sqrt{\frac{x}{y}}$
D
$\frac{\sqrt[3]{x}}{\sqrt{y}}$
✓ Correct! Well done.
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