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JEE MAIN 2019
11-01-2019 S2
Question
A compound ' $X$ ' on treatment with $\mathrm{Br}_2 / \mathrm{NaOH}$, provided $\mathrm{C}_3 \mathrm{H}_9 \mathrm{~N}$, which gives positive carbylamine test. Compound ' X ' is :
Select the correct option:
A
$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CONH}_2$
B
$\mathrm{CH}_3 \mathrm{COCH}_2 \mathrm{NHCH}_3$
C
$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COCH}_2 \mathrm{NH}_2$
D
$\mathrm{CH}_3 \mathrm{CON}\left(\mathrm{CH}_3\right)_2$
✓ Correct! Well done.
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