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JEE MAIN 2020
06-09-2020 S2
Question
The linear mass density of a thin rod $A B$ of length $L$ varies from $A$ to $B$ as $$ \lambda(x)=\lambda_0\left(1+\frac{x}{L}\right) $$ , where x is the distance from $A$. If $M$ is the mass of the rod then its moment of inertia about an axis passing through A and perpendicular to the rod is
Select the correct option:
A
$\frac{2}{5} \mathrm{ML}^2$
B
$\frac{5}{12} \mathrm{ML}^2$
C
$\frac{3}{7} M L^2$
D
$\frac{7}{18} \mathrm{ML}^2$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Physics
Easy
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