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JEE MAIN 2019
10-04-2019 S2
Question
If $\cos ^{-1} x-\cos ^{-1} \frac{y}{2}=\alpha$, where $1 \leq x \leq 1,-2 \leq y \leq 2$, $x \leq \frac{y}{2}$, then for all $x, y, 4 x^2-4 x y \cos \alpha+y^2$ is equal to:
Select the correct option:
A
$2 \sin ^2 \alpha$
B
$4 \sin ^2 \alpha-2 x^2 y^2$
C
$4 \cos ^2 \alpha+2 x^2 y^2$
D
$4 \sin ^2 \alpha$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Question Tags
JEE Main
Mathematics
Hard
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