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JEE MAIN 2019
09-04-2019 - S1
Question
The standard Gibbs energy for the given cell reaction in kJ mol–1 at 298 K is
$\mathrm{Zn}(\mathrm{s})+\mathrm{Cu}^{2+}(\mathrm{aq}) \longrightarrow \mathrm{Zn}^{2+}(\mathrm{aq})+\mathrm{Cu}(\mathrm{s})$,
$\mathrm{E}^{\circ}=2 \mathrm{~V}$ at 298 K
(Faraday’s constant, F = 96000 C mol–1)
Select the correct option:
A
192
B
384
C
–384
D
–192
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Chemistry
Easy
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