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JEE MAIN 2019
09-01-19 S2
Question
Consider the following reversible chemical reactions
$ \begin{aligned} & \mathrm{A}_2(\mathrm{~g})+\mathrm{B}_2(\mathrm{~g}) \stackrel{\mathrm{K}_1}{\rightleftharpoons} 2 \mathrm{AB}(\mathrm{~g}) \\ & 6 \mathrm{AB}(\mathrm{~g}) \stackrel{\mathrm{K}_2}{\rightleftharpoons} 3 \mathrm{~A}_2(\mathrm{~g})+3 \mathrm{~B}_2(\mathrm{~g}) \end{aligned} $
The relation between $\mathrm{K}_1$ and $\mathrm{K}_2$ is
Select the correct option:
A
$K_2=K_1^3$
B
$K_1 K_2=\frac{1}{3}$
C
$K_2=K_1{ }^{-3}$
D
$K_1 K_2=3$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Chemistry
Easy
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