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JEE MAIN 2020
09-01-20 S1
Question
The integral $\int \frac{d x}{(x+4)^{\frac{8}{7}}(x-3)^{\frac{6}{7}}}$ is equal to (where C is a constant of integration)
Select the correct option:
A
$-\frac{1}{2}\left(\frac{x-3}{x+4}\right)^{3 / 7}+C$
B
$-\frac{1}{13}\left(\frac{x-3}{x+4}\right)^{-13 / 7}+C$
C
$\left(\frac{x-3}{x+4}\right)^{1 / 7}+C$
D
$-\left(\frac{x-3}{x+4}\right)^{-1 / 7}+C$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Medium
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