Gravitation | JEE Main 2025 Solution

JEE MAIN 2025

24-01-2025 SHIFT-1

Question

A satellite is launched into a circular orbit of radius 'R' around the earth. A second satellite is launched into an orbit of radius 1.03 R. The time period of revolution of the second satellite is larger than the first one approximately by

Select the correct option:

4.5%

2.5%

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Solution

${{\rm{T}}^2} = {\rm{K}}{{\rm{R}}^3}$
$\frac{{2\Delta \;{\rm{T}}}}{{\;{\rm{T}}}} = \frac{{3\Delta {\rm{R}}}}{{\rm{R}}}$
$\frac{{2\Delta \;{\rm{T}}}}{{\;{\rm{T}}}} = \frac{{3 \times 0.03{\rm{R}}}}{{\rm{R}}}$
$\frac{{\Delta \;{\rm{T}}}}{{\;{\rm{T}}}} = \frac{{3 \times 0.03}}{2} \times 100 = 4.5\% $

Question Tags

JEE Main

Physics

Easy

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