Solution A is prepared by dissolving 1 g of a protein (molar mass $=50000 \mathrm{~g} \mathrm{~mol}^{-1}$ ) in 0.5 L of water at 300 K . Its osmotic pressure is $x$ bar. Solution B is made by dissolving 2 g of same protein in 1 L of water at 300 K . Osmotic pressure of solution B is $y$ bar. Entire solution of A is mixed with entire solution of B at same temperature. The osmotic pressure of resultant solution is $z$ bar, $\mathrm{x}, \mathrm{y}$ and z respectively are : $\left(\mathrm{R}=0.083 \mathrm{~L}\right.$ bar $\left.\mathrm{mol}^{-1} \mathrm{~K}^{-1}\right)$