A ratio of the 5th term from |Binomial Theorem|JEEMAIN 2019

JEE-MAIN 2019

12-01-2019 S1

Question

A ratio of the 5 th term from the beginning to the $5^{\text {th }}$ term from the end in the binomial expansion of $\left(2^{\frac{1}{3}}+\frac{1}{2(3)^{\frac{1}{3}}}\right)^{10}$ is

Select the correct option:

(1) $1: 4(16)^{\frac{1}{3}}$

$1: 2(6)^{\frac{1}{3}}$

$2(36)^{\frac{1}{3}}: 1$

$4(36)^{\frac{1}{3}}: 1$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

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