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JEE MAIN 2019
12-4-19_S1
Question
What is the molar solubility of $\mathrm{Al}(\mathrm{OH})_3$ in 0.2 M NaOH solution? Given that, solubility product of $\mathrm{Al}(\mathrm{OH})_3=2.4 \times 10^{-2}$
Select the correct option:
A
$3 \times 10^{-19}$
B
$12 \times 10^{-21}$
C
$12 \times 10^{-23}$
D
$3 \times 10^{-22}$
✓ Correct! Well done.
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Solution
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Question Tags
JEE Main
Chemistry
Medium
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