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JEE ADVANCED 2025
Paper-2 2025
Question
Six infinitely large and thin non-conducting sheets are fixed in configurations I and II. As shown in the figure, the sheets carry uniform surface charge densities which are indicated in terms of $\sigma 0$. The separation between any two consecutive sheets is 1m. The various regions between the sheets are denoted as $1,2,3,4$ and 5 . If $\sigma_0=9 \mu \mathrm{C} / \mathrm{m}^2$, then which of the following statements is/are correct: (Take permittivity of free space $\epsilon_0=9 \times 10^{-12} \mathrm{~F} / \mathrm{m}$ )
Select the correct option:
A
In region 4 of the configuration I, the magnitude of the electric field is zero.
B
In region 3 of the configuration II, the magnitude of the electric field is $\frac{\sigma_0}{\epsilon_0}$.
C
Potential difference between the first and the last sheets of the configuration I is 5 V .
D
Potential difference between the first and the last sheets of the configuration II is zero.
✓ Correct! Well done.
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Solution
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Question Tags
JEE Advance
Physics
Easy
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