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JEE-Advanced 2025
PAPER-2 2025
Question
At 300 K , an ideal dilute solution of a macromolecule exerts osmotic pressure that is expressed in terms of the height ( h ) of the solution (density = $1.00 \mathrm{~g} \mathrm{~cm}{ }^{-3}$ ) where h is equal to $2.00 \mathrm{~cm}^{\circ}$ If the concentration of the dilute solution of the macromolecule is $2.00 \mathrm{gdm}^{-3}$, the molar mass of the macromolecule is calculated to be $\mathbf{X} \times 10^4 \mathrm{~g} \mathrm{~mol}^{-1}$. The value of $\mathbf{X}$ is $\_\_\_\_$ . Use: Universal gas constant $(R)=8.3 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ and acceleration due to gravity $(g)=10 \mathrm{~m} \mathrm{~s}^{-2}$
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Question Tags
JEE Advance
Chemistry
Easy
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