Report Issue

JEE MAIN_2019_
10-04-2019-S-1
Question
$\lim _{n \rightarrow \infty}\left(\frac{(n+1)^{1 / 3}}{n^{4 / 3}}+\frac{(n+2)^{1 / 3}}{n^{1 / 3}}+\ldots . .+\frac{(2 n)^{1 / 3}}{n^{4 / 3}}\right)$ is equal to:
Select the correct option:
A
$\frac{4}{3}(2)^{4 / 6}$
B
$\frac{3}{4}(2)^{4 / 3}-\frac{3}{4}$
C
$\frac{4}{3}(2)^{3 / 4}$
D
$\frac{3}{4}(2)^{4 / 6}-\frac{4}{3}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Solution Image
Question Tags
JEE Main
Mathematics
Hard
Start Preparing for JEE with Competishun