80 mL of a hydrocarbon..... | JEE Main 2026 | Mole Concept

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80 mL of a hydrocarbon on mixing with 264 mL of oxygen in a closed U-tube undergoes complete combustion. The residual gases after cooling to 273 K occupy 224 mL . When the system is treated with KOH solution, the volume decreases to 64 mL . The formula of the hydrocarbon is:

Select the correct option:

A

$\mathrm{C}_2 \mathrm{H}_4$

B

$\mathrm{C}_4 \mathrm{H}_{10}$

C

$\mathrm{C}_2 \mathrm{H}_2$

D

$\mathrm{C}_2 \mathrm{H}_6$

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