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JEE MAIN 2026
22-01-2026 S2
Question
If $y=y(x)$ satisfies the differential equation $16(\sqrt{x+9 \sqrt{x}})(4+\sqrt{9+\sqrt{x}}) \cos y \mathrm{~d} y=(1+2 \sin y) \mathrm{d} x, x>0$ and $y(256)=\frac{\pi}{2}, y(49)=\alpha$, then $2 \sin \alpha$ is equal to:
Select the correct option:
A
$3(\sqrt{2}-1)$
B
$2(\sqrt{2}-1)$
C
$2 \sqrt{2}-1$
D
$\sqrt{2}-1$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Hard
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