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JEE MAIN 2026
23-01-2026 S2
Question
A student has been given a compound " $x$ " of molecular formula- $\mathrm{C}_6 \mathrm{H}_7 \mathrm{~N} \cdot x$ ' is sparingly soluble in water. However, on addition of dilute mineral acid, ' $x$ ' becomes soluble in water. ' $x$ ' when treated with $\mathrm{CHCl}_3$ and $\mathrm{KOH}($ alc), ' $y$ ' is produced. ' $y$ ' has a specific unpleasant smell. On treatment with benzenesulphonyl chloride, ${ }^{\prime} x$ ' gives a compound' $z$ ' which is soluble in alkali. The number of different " H " atoms present in ' z ' is:-
Select the correct option:
A
5
B
8
C
4
D
7
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Chemistry
Hard
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