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JEE MAIN 2026
24-01-26 S1
Question
'W' g of a non-volatile electrolyte solid solute of molar mass ${ }^{\prime} \mathrm{M}^{\prime} \mathrm{gmol}^{-1}$ when dissolved in 100 mL water, decreases vapour pressure of water from 640 mm Hg to 600 mm Hg . If aqueous solution of the electrolyte boils at $375 \mathrm{~K}^{\circ}$ and $\mathrm{K}_{\mathrm{b}}$ for water is $0.52 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$, then the mole fraction of the electrolyte solute ( $x_2$ ) in the solution can be expressed as (Given : density of water $=1 \mathrm{~g} / \mathrm{mL}$ and boiling point of water $=373 \mathrm{~K}$ )
Select the correct option:
A
$\frac{1.3}{8} \times \frac{W}{M}$
B
$\frac{16}{2 \cdot 6} \times \frac{W}{M}$
C
$\frac{2 \cdot 6}{16} \times \frac{\mathrm{M}}{\mathrm{W}}$
D
$\frac{1.3}{8} \times \frac{\mathrm{M}}{\mathrm{W}}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Chemistry
Easy
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