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JEE MAIN_2026
_280126_S2
Question
The wavelength of photon ' $A$ ' is 400 nm . The frequency of photon ' $B$ ' is $10^{16} \mathrm{~s}^{-1}$. The wave number of photon ' $C$ ' is $10^4 \mathrm{~cm}^{-1}$. The correct order of energy of these photons is :
Select the correct option:
A
$\mathrm{C}>\mathrm{B}>\mathrm{A}$
B
$\mathrm{B}>\mathrm{A}>\mathrm{C}$
C
$A>B>C$
D
$\mathrm{A}>\mathrm{C}>\mathrm{B}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
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