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JEE MAIN 2025
02-04-2025 SHIFT-1
Question
Let ${B_1}$ be the magnitude of magnetic field at center of a circular coil of radius R carrying current I. Let ${B_2}$ be the magnitude of magnetic field at an axial distance 'x' from the center. For $x:R = 3:4,\frac{{{B_2}}}{{{B_1}}}$ is :
Select the correct option:
A
25 : 16
B
16 : 25
C
4 : 5
D
64 : 125
✓ Correct! Well done.
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Solution
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Question Tags
JEE Main
Physics
Easy
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