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JEE MAIN 2025
23-01-2025 SHIFT-2
Question
Consider the following reactions $$ \mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} \xrightarrow[-\mathrm{H}_{2} \mathrm{O}]{\mathrm{KOH}}[\mathrm{~A}] \xrightarrow[-\mathrm{H}_{2} \mathrm{O}]{\mathrm{H}_{2} \mathrm{O}_{4}}[\mathrm{~B}]+\mathrm{K}_{2} \mathrm{SO}_{4} $$ The products $[\mathrm{A}]$ and $[\mathrm{B}]$, respectively are :
Select the correct option:
A
$\mathrm{K}_{2} \mathrm{Cr}(\mathrm{OH})_{6}$ and $\mathrm{Cr}_{2} \mathrm{O}_{3}$
B
$\mathrm{K}_{2} \mathrm{CrO}_{4}$ and CrO
C
$\mathrm{K}_{2} \mathrm{CrO}_{4}$ and $\mathrm{Cr}_{2} \mathrm{O}_{3}$
D
$\mathrm{K}_{2} \mathrm{CrO}_{4}$ and $\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$\quad \mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} \xrightarrow[-\mathrm{H}_{2} \mathrm{O}]{\mathrm{KOH}} \mathrm{K}_{2} \mathrm{CrO}_{4} \xrightarrow[-\mathrm{H}_{2} \mathrm{O}]{\mathrm{H}_{2} \mathrm{SO}_{4}} \underset{[\mathrm{~B}]}{\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}}+\mathrm{K}_{2} \mathrm{SO}_{4}$
Question Tags
JEE Main
Chemistry
Easy
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