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JEE Advanced 2024
Paper-1 2024
Multiple correct answers - Select all that apply
Question
Two uniform strings of mass per unit length $\mu$ and $4 \mu$, and length $L$ and 2 L , respectively, are joined at point $O$, and tied at two fixed ends $P$ and $Q$, as shown in the figure. The strings are under a uniform tension $T$. If we define the frequency $v_0=\frac{1}{2 L} \sqrt{\frac{T}{\mu}}$, which of the following statement (s) is (are) correct?
Select ALL correct options:
A
With a node at , the minimum frequency of vibration of the composite string is $ v_0$
B
With an antinode at $O$, the minimum frequency of vibration of the composite string is $2 v_0$
C
When the composite string vibrates at the minimum frequency with a node at $O$, it has 6 nodes, including the end nodes
D
No vibrational mode with an antinode at $O$ is possible for the composite string
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
⚠ Partially correct. Some answers are missing.
Solution
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Question Tags
JEE Advance
Physics
Medium
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