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JEE MAIN 2025
04-04-2025 SHIFT-1
Question
Rate law for a reaction between A and B is given by
${\rm{r}} = {\rm{k}}{[\;{\rm{A}}]^{\rm{n}}}{[\;{\rm{B}}]^{\rm{m}}}$
If concentration of A is doubled and concentration of B is halved from their initial value, the ratio of new rate of reaction to the initial rate of reaction $\left( {\frac{{{r_2}}}{{{r_1}}}} \right)$ is
Select the correct option:
A
$({\rm{n}} - {\rm{m}})$
B
$({\rm{m}} + {\rm{n}})$
C
$\frac{1}{{{2^{m + n}}}}$
D
${2^{({\rm{n}} - m)}}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Chemistry
Easy
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