The Ksp of Ag₂CrO₄ is 1.1 × 10...| JEE Advanced 2013 | Ionic

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The $\mathrm{K}_{\mathrm{sp}}$ of $\mathrm{Ag}_2 \mathrm{CrO}_4$ is $1.1 \times 10^{-12}$ at 298 K . The solubility (in $\mathrm{mol} / \mathrm{L}$ ) of $\mathrm{Ag}_2 \mathrm{CrO}_4$ in a $0.1 \mathrm{M} \mathrm{AgNO}_3$ solution is

Select the correct option:

A

$1.1 \times 10^{-11}$

B

$1.1 \times 10^{-10}$

C

$1.1 \times 10^{-12}$

D

$1.1 \times 10^{-9}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

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