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JEE Advance 2008
paper 1
Question
Consider the functions defined implicitly by the equation $y^3-3 y+x=0$ on various intervals in the real line. If $x \in(-\infty,-2) \cup(2, \infty)$, the equation implicitly defines a unique real valued differentiable function $y=f(x)$. If $\mathrm{x} \in(-2,2)$, the equation implicitly defines a unique real valued differentiable function $\mathrm{y}=\mathrm{g}(\mathrm{x})$ satisfying $\mathrm{g}(0)=0$.
The area of the region bounded by the curves $y=f(x)$, the $x$-axis, and the lines $x=a$ and $x=b$,where $-\infty<\mathrm{a}<\mathrm{b}<-2$, is
Select the correct option:
A
$\int_{\mathrm{a}}^{\mathrm{b}} \frac{\mathrm{x}}{3\left((\mathrm{f}(\mathrm{x}))^2-1\right)} \mathrm{dx}+\mathrm{bf}(\mathrm{b})-\mathrm{af}(\mathrm{a})$
B
$-\int_{\mathrm{a}}^{\mathrm{b}} \frac{\mathrm{x}}{3\left((\mathrm{f}(\mathrm{x}))^2-1\right)} \mathrm{dx}+\mathrm{bf}(\mathrm{b})-\mathrm{af}(\mathrm{a})$
C
$\int_{\mathrm{a}}^{\mathrm{b}} \frac{\mathrm{x}}{3\left((\mathrm{f}(\mathrm{x}))^2-1\right)} \mathrm{dx}-\mathrm{bf}(\mathrm{b})+\mathrm{af}(\mathrm{a})$
D
$-\int_{\mathrm{a}}^{\mathrm{b}} \frac{\mathrm{x}}{3\left((\mathrm{f}(\mathrm{x}))^2-1\right)} \mathrm{dx}-\mathrm{bf}(\mathrm{b})+\mathrm{af}(\mathrm{a})$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
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