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JEE Advance 2006
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Question
The axis of a parabola is along the line $\mathrm{y}=\mathrm{x}$ and the distance of its vertex from origin is $\sqrt{2}$ and that from its focus is $2 \sqrt{2}$. If vertex and focus both lie in the first quadrant, then the equation of the parabola is
Select the correct option:
A
$(x+y)^2=(x-y-2)$
B
$(x-y)^2=(x+y-2)$
C
$(x-y)^2=4(x+y-2)$
D
$(x-y)^2=8(x+y-2)$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
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