DEFINITE INTEGRATION_JEE_MAIN_27-01-2024_(s2) - Competishun – Live JEE & NEET Courses and Exam Prep

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JEE-Main 2024

27-01-24 S2

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Let $f(x)=\int_0^x g(t) \log _e\left(\frac{1-t}{1+t}\right) d t$, where $g$ is a continuous odd function. If $\int_{-\pi / 2}^{\pi / 2}\left(f(x)+\frac{x^2 \cos x}{1+e^x}\right) d x=\left(\frac{\pi}{\alpha}\right)^2-\alpha$, then $\alpha$ is equal to.

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JEE Main

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