Electronegativity Order | JEE Main 2025

JEE MAIN 2025

02-04-2025 SHIFT-2

Question

Electronic configuration of four elements $\mathrm{A}, \mathrm{B}, \mathrm{C}$ and D are given below :
(A) $1 s^{2} 2 s^{2} 2 p^{3}$
(B) $1 s^{2} 2 s^{2} 2 p^{4}$
(C) $1 s^{2} 2 s^{2} 2 p^{5}$
(D) $1 s^{2} 2 s^{2} 2 p^{2}$
Which of the following is the correct order of increasing electronegativity (Pauling's scale) ?

Select the correct option:

A < C < B < D

A < B < C < D

A < D < B < C

D < A < B < C

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

$\quad N:-1 s^{2} 2 s^{2} 2 p^{3}($ Electronegativity $=3)$
$O:-1 s^{2} 2 s^{2} 2 p^{4}($ Electronegativity $=3.5)$
$F:-1 s^{2} 2 s^{2} 2 p^{5}($ Electronegativity $=4)$
$C:-1 s^{2} 2 s^{2} 2 p^{2}($ Electronegativity $=2.55)$
Correct order $=\mathrm{C}>\mathrm{B}>\mathrm{A}>\mathrm{D}$

Question Tags

JEE Main

Chemistry

Easy

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