Ionic Equilibrium_JEE Main_02-04-2026_S1 - Competishun – Live JEE & NEET Courses and Exam Prep

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JEE MAIN 2026

02-04-2026 S1

Question

The solubility product constants of $\mathrm{Ag}_2 \mathrm{CrO}_4$ and AgBr are 32 x and 4 y respectively at 298 K . The value of $\left(\frac{\text { molarity of } \mathrm{Ag}_2 \mathrm{CrO}_4}{\text { molarity of } \mathrm{AgBr}}\right)$ can be expressed as :

Select the correct option:

A

$\frac{2 \sqrt[3]{x}}{y}$

B

$2 \sqrt{\frac{x}{y}}$

C

$\sqrt{\frac{x}{y}}$

D

$\frac{\sqrt[3]{x}}{\sqrt{y}}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

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