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JEE MAIN 2020
02-09-2020 S2
Question
A $10 \mu \mathrm{~F}$ capacitor is fully charged to a potential difference of 50 V . After removing the source voltage it is connected to an uncharged capacitor in parallel. Now the potential difference across them becomes 20 V . The capacitance of the second capacitor is
Select the correct option:
A
$20 \mu \mathrm{~F}$
B
$10 \mu \mathrm{~F}$
C
$15 \mu \mathrm{~F}$
D
$30 \mu \mathrm{~F}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$\begin{aligned} & V_{\text {final }}=\frac{C_1 V}{C_1+C_2} \\ & C_2=15 \mu F\end{aligned}$
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