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JEE MAIN 2019
11-01-2019 S2
Question
A 27 mW laser beam has a cross-sectional area of $10 \mathrm{~mm}^2$. The magnitude of the maximum electric field in this electromagnetic wave is given by: [Given permittivity of space $\epsilon_0=9 \times 10^{-12} \mathrm{SI}$ units, Speed of light $\mathrm{c}=3 \times 10^8$ m/s]
Select the correct option:
A
$1.4 \mathrm{kV} / \mathrm{m}$
B
$1 \mathrm{kV} / \mathrm{m}$
C
$2 \mathrm{kV} / \mathrm{m}$
D
$0.7 \mathrm{kV} / \mathrm{m}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Physics
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