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JEE MAIN 2022
29-07-2022 S2
Question
A 8 V Zener diode along with a series resistance R is connected across a 20 V supply (as shown in the figure). If the maximum Zener current is 25 mA, then the minimum value of R will be_____$\Omega$.
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Solution
$\begin{aligned} & \varepsilon-I R-V_Z=0 \\ & 20-I R-6=0 \\ & I R=12 \\ & 25 \times 10^{-3} R=12 \\ & R=\frac{12}{25 \times 10^{-3}}=480 \Omega\end{aligned}$
Question Tags
JEE Main
Physics
Medium
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