A ball is thrown upward | Kinetic Theory

JEE MAIN_2019_

S1_100419

Question

A ball is thrown upward with an initial velocity V 0 from the surface of the earth. The motion of the ball is affected by a drag force equal to $\mathrm{m}_{\mathrm{r}} \mathrm{v} 2$ (where $m$ is mass of the ball, $v$ is its instantaneous velocity and $\gamma$ is a constant). Time taken by the ball to rise to its zenith is:

Select the correct option:

$\frac{1}{\sqrt{/ g}} \sin ^{-1}\left(\sqrt{\frac{7}{g}} \mathrm{v}_0\right)$

$\frac{1}{\sqrt{/ g}} \ln \left(1+\sqrt{\frac{7}{g}} \mathrm{v}_0\right)$

$\frac{1}{\sqrt{\sqrt{9}}} \tan ^{-1}\left(\sqrt{\frac{\gamma}{9}} \mathrm{v}_0\right)$

$\frac{1}{\sqrt{2 \gamma g}} \tan ^{-1}\left(\sqrt{\frac{2 \gamma}{g}} \mathrm{v}_0\right)$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution