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JEE Advanced 2014
Paper-2 2014
Question
A block of mass $m_1=1 \mathrm{~kg}$ another mass $m_2=2 \mathrm{~kg}$, are placed together (see figure) on an inclined plane with angle of inclination $\theta$. Various values of $\theta$ are given in List $I$. The coefficient of friction between the block $m_1$ and the plane is always zero. The coefficient of static and dynamic friction between the block $m_2$ and the plane are equal to $\mu=0.3$. In List II expression for the friction on block $m_2$ given. Match the correct expression of the friction in List II with the angles given in List I, and choose the correct option. The acceleration due to gravity is denoted by g . [Useful information : $\tan \left(5.5^{\circ}\right) \approx 0.1 ; \tan \left(11.5^{\circ}\right) \approx 0.2 ; \tan \left(16.5^{\circ} \approx 0.3\right)$ ]
Select the correct option:
A
P-1, Q-1, R-1,S-3
B
P-2, Q-2, R-2,S-3
C
P-2, Q-2, R-2,S-4
D
P-2, Q-2, R-3,S-3
✓ Correct! Well done.
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Solution
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Question Tags
JEE Advance
Physics
Easy
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